# How much hydrogen will be released when sodium interacts with 2 mol of glycerin?

October 14, 2021 | education

| Solution: write down the reaction equation for the interaction of sodium with glycerin.

2С3Н5 (ОН) 3 + 2Na = 2CH2O – Na – CHOH – CH2 – OH + H2 – substitution reaction, glycerin interacts with metallic sodium with an explosion, while hydrogen is released;

It follows from the reaction equation that 2 mol of glycerol, interacting with sodium, form X mol of hydrogen.

Let’s make the proportion:

2 mol С3Н5 (ОН) 3 – х mol Н2

2 mol 1 mol X mol (H2) = 2 * 1/2 = 1 mol

Determine the volume of hydrogen:

V (H2) = 1 * 22.4 = 22.4 liters (according to Avogadro’s law)

Answer: 22.4 liters of hydrogen are released.

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